4. Find the equations of the following lines:a. having slope of -2 and passing through the point (-4, 2)b. parallel to y = 6x + 3 and passing through the point (-1, 13)c. perpendicular to 3x – 5y = 5 and having an x-intercept of 3d. passing through (-2, -6) and (4, 2)e. having an x-intercept of -3 and a y-intercept of 6This is frustrating me to no end!!! Please Help!

Answer:Step-by-step explanation:The general equation for a line is given by: y = mx + n (m: slope, n: y-intercept)a) given: m = -2, x = -4, y = 2equation becomes: 2 = -2 * (-4) + nsolve for n: n = -6solution: y = -2x - 6b)given: m = 6, x = -1, y = 13equation becomes: 13 = 6 * (-1) + nsolve for n: n = 19solution: y = 6x + 19c)given: perpendicular to: y = 3/5x - 1 => m = -5/3, x = 3, y = 0equation becomes: 0 = (-5/3) * 3 + nsolve for n: n = 5solution: y = -5/3x + 5d) get the slope m from the two points. given: m = Δy/Δx = 8/6 = 4/3, x = 4, y = 2equation becomes: 2 = (4/3) * 4 + nsolve for n: n = -10/3solution: y = (4/3)x - (10/3)e) given: point1 (-3,0), point2(0,6)m = Δy/Δx = 6/3 = 2, x = 0, y = 6equation becomes: 6 = 0 + nsolve for n: n = 6solution: y = 2x + 6